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Reptile [31]
3 years ago
7

A study of the effects of color on easing anxiety compared anxiety test scores of participants who completed the test printed on

soft yellow paper versus a different group of students who completed the test printed on harsh green paper. The scores for five participants who completed the test printed on the yellow paper were 17, 19, 28, 21, and 18. The scores for four participants who completed the test on the green paper were 20, 26, 17, and 24. Using the .05 significance level, one-tailed (predicting lower anxiety scores for the yellow paper), what should the researcher conclude
Mathematics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

Step-by-step explanation:

To solve this, we would follow these simple steps. We have

unvrs :

The arithmetic mean, x-bar for the yellow paper group (Y) = 20.6

The arithmetic mean, x-bar for the green paper group (G) = 21.75

Recall that, H0: µY = µG

And from the data we have, we can see that

H0: µY< µG

We proceed to say that the

T-Test-statistic = -0.404

Also, the p-value: 0.349

From our calculations, we can see that the p-value > 0.05, and as such, we conclude that we will not reject H0. This is because there is not enough evidence to show that test that is printed on the yellow paper decreases anxiety at a 0.05 significance level.

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Answer:

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Step-by-step explanation:

First off, we use commutative property to get the like terms together.

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Now we can solve the equations inside the parenthesis.

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Find d<br><br> a * a * a = 216<br> a * b * c = 96<br> b * c = 52<br> a + b + c = d
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a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6

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<h3>Answer: NO SOLUTION.</h3>
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