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Sergeu [11.5K]
2 years ago
7

Solve for x. Round to the nearest hundredth.

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
8 0
<h3>Answer:  Choice D)  12.27</h3>

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(64) = x/28

x/28 = cos(64)

x = 28*cos(64)

x = 12.2743921100941

x = 12.27

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Which equation can be used to solve for the value of n if 2 + n = 12?
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How to find a missing angle
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In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

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3 years ago
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alexira [117]

Answer:

8,13,18

Step-by-step explanation:

n=1

8+5(0)=8

n=2

8+5(1)=13

n=3

8+5(2)=18

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3 years ago
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