Find the area of a circle with a diameter of 12 meters. round to the nearest tenth
2 answers:
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Answer:
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.
where <em>a</em> and<em> b</em> are the legs and <em>c</em> is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:
- a= 9 cm
- b= 11 cm
Substitute these values into the formula.
Solve the exponents.
- (9 cm)²= 9 cm*9 cm=81 cm²
- (11 cm)²= 11 cm*11 cm= 121 cm²
Add the values on the left side.
Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.
We are told to round to the nearest tenth.
- 14.2<u>1</u>26704036
The 1 in the hundredth place tells us to leave the 2 in the tenth place.
The hypotenuse is equal to <u>14.2 centimeters.</u>
Answer:
105degrees
Step-by-step explanation:
Using the theorems that states that the sum of the opposite side of the quadrilateral is 180degrees, hence;
<RST + <TQR = 180
5x+15 + 4x+ 3 = 180
9x + 18 = 180
9x = 180 - 18
9x = 162
x = 162/9
x = 18
Since <RST = 5x+15
<RST = 5(18) + 15
<RST = 90 + 15
<RST = 105degrees
Hence the measure of <RST is 105degrees
