MKL = 83, JKL = 127, JKM = 9x - 10 <em>given</em>
JKL + MKL = JKM <em>angle addition postulate</em>
127 + 83 = 9x - 10 <em>substitution</em>
210 = 9x - 10 <em>simplify (add like terms)</em>
220 = 9x <em>addition property of equality</em>
= x
Answer:
6 4/9
Step-by-step explanation:
You divide 58 and 8 and your answer would be 6.444444 repeating.
Answer:
(-6, -3)
Step-by-step explanation:
The coordinate is at (2, -1), when using a dilation with a scale factor of 3, multiply the coordinates by 3.
(2, -1) ------> (2 x 3, -1 x 3) ----------> (6, -3)
When reflecting the point over the y-axis, take the opposite of the x coordinate.
(6, -3) ------> (-6, -3)
Answer:
Step-by-step explanation:
The question is asking you to graph the equations.
The equations are in slope intercept form so y=mx+b
M is the slope and b is the y-intercept
First draw the y & x axis and label/number them
The y-intercept for the first equation is -1 so draw a dot on the -1 on the y-axis
The slope is 2/5 and you use rise/run to continue the slope.
you rise 2 on the y-axis and go right 5 times on the x-axis (for a negative number you go left/down)
For the second equation, you have to turn it into slope intercept form.
You should get y=2/3x+3
You graph this equation the same as you did the first one.