Need part b
Have a nice day
No, she didn't because 5:7 and 12:8 are not equivalent ratios
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Answer:
x = 10°; angles are 50°, 46°, 84° (CW from left)
Step-by-step explanation:
The sum of the three angles is 180°, so ...
(6x +10°) +(4x +6°) +(7x +14°) = 180°
17x +10° = 180°
17x = 170°
x = 10°
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Then the angles are ...
6x -10° = 6·10° -10° = 50°
4x +6° - 4·10° +6° = 46°
7x +14° = 7·10° +14° = 84°
Answer: AB ≅ CB
Step-by-step explanation:
In the given figure, we have ∆ABD ≅ ∆CBD
The CPCTC property of congruent triangles says that if two triangles are congruent then their corresponding parts ( angles and segments ) are congruent.
Since we have given that ∆ABD ≅ ∆CBD.
Therefore, the corresponding segments are congruent.
As segment AB is corresponding to segment CB. [First two letters]
Therefore, segment AB is congruent to segment CB.
P = 2l + 2w
p-2w = 2l
p-2w/2 = l
Substitute the perimeter and you should be able to work it out
