Do you have the specific point??
Remember, if 2 lines are perpendicular, their slopes are opposite reciprocals. So if one line has a slope of 4, the other line should have a slope of -1/4.
Hopefully your equation is in y=mx+b form. If so,
make sure you know slope (m) and the y-intercept. After this is done, plug in the points from p for y and x, and make sure to turn m into -1/m. Solve for b, and your new equation should be y=(new slope)x+(new y-intercept)
<h3>
Answer:</h3>
f(x) = -(x -2)² +3
<h3>
Step-by-step explanation:</h3>
We can fill in the vertex (h, k) values immediately in the vertex form ...
... f(x) = a(x -h)² +k
To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:
... -1 = a(0 -2)² +3
... -4 = 4a . . . . . . . . . subtract 3, simplify
... -1 = a . . . . . . . . . . . divide by 4
Now, we know the function is ...
... f(x) = -(x -2)² +3
Two points of the slope y=(2x+2) - 3 are (-1,0), (0,1)
Answer:
It would be -81²x+81x-18= -9x+6
Step-by-step explanation:
When you work equation one you get 18. Then when you work equation two, you get -2/3=-0.666666667
