The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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Answer: The answer is (y^2) to the power of -0.5
Step-by-step explanation:
Answer:
rubbing it against your hair it causes friction and with friction comes energy
Answer:
Step-by-step explanation:
slope = y₂-y₁/x₂-x₁
Answer:
1120 grams
Step-by-step explanation:
The amount of sea water is directly proportional to the amount of salt in the water.
Let the amount of sea water be W and the amount of salt be S.
This means that:
W α S
=> W = kS
where k = constant of proportionality
2 liters of sea water contain 70 grams of salt Therefore:
2 = k * 70
k = 2 / 70 = 1/35
Therefore, for 32 liters of sea water:
32 = 1/35 * S
S = 35 * 32
S = 1120 grams
There are 1120 grams of salt in 32 liters of water.
