Answer:
8?
Step-by-step explanation:
Question 1:
Since the triangles are congruent, we know that QS = TV
This means that
3v + 2 = 7v - 6
Subtract both sides by 2
3v = 7v - 8
Subtract 7v from both sides
-4v = -8
Divide both sides by -4
v = 2
Plug this value back into 3v + 2 and you get 8.
QS = 8
Since the triangles are congruent
QS = 8 AND TV = 8
Question 2:
So we know that AC = AC because that's a shared side.
It's also given that BC = CD.
In order for two triangles to be congruent by SAS, the angle between the two sides must be congruent.
That means angle C must be congruent to angle C from the other triangle.
Question 3:
We know that AC = AC because it's a shared side.
We also know that angle A from one triangle is equal to angle C from the other.
However, for a triangle to be congruent by SAS, the congruent angle must be between two congruent sides.
In order for us to prove congruence by SAS, AD must be congruent to BC.
Have an awesome day! :)
We can find critical value by using t - table.
For using t - table we need degree of freedom and alpha either for two tailed test or one tailed test.
We can determine degree of freedom by subtracting sample size from one.
So in given question sample size is 23. So we can say degree of freedom(df) for sample size 23 is
df = 23 - 1= 22
Now we have to go on row for degree of freedom 22.
After that we need to find alpha either for two tailed test or one tailedl test.
Confidence level is 99%. We can convert it into decimal as 0.99.
So alpha for two tailed test is 100 - 0.99 = 0.01
Alpha for one tailed test is 0.01/2 = 0.005.
So we will go on column for 0.01 for two tailed test alpha or 0.005 for one tailed test alpha.
SO the critical value 22 degree of freedom and 0.01 two tailed alpha is 2.819 from t - table.
Answer:
Convert 8 1/2 to 8.5 and 6 3/10 to 6.3, and then multiply 8.5 by 6.3. Answer:
53.55, or, if you reduce 55/100, 53 11/20.
Step-by-step explanation:
Answer:
41
Step-by-step explanation:
Add the numbers together and divide by 5. 5 is the amount of numbers in the example.
