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2 years ago

Helppp!!! 0_o 70 pnts!!!

Mathematics

2 answers:

kati45 [8]2 years ago

8 0

Answer:

Option A is correct

Step-by-step explanation:

For the box y=mx+c

Hope this helps

KIM [24]2 years ago

3 0

Its A.

If you need something more explained go to the other answer.

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Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zigmanuir [339]

Answer:

$P(E \cup F)=P(E)+P(F)$ .

Step-by-step explanation:

Given the statement

If $P(E)+P(F)=P(E \cup F)+P(E \cap F)$ , then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

$P(E \cup F)=P(E)+P(F)$ .

3 0

3 years ago

Find the diameter of a circle with an area of 6767 square centimeters.

scZoUnD [109]

Area=6767cm²

Diameter be d

Radius be r

πr²=6767
r²=6767/π
r²=2155
r=46.4cm

Diameter=2r=46.4(2)=92.8cm

6 0

2 years ago

Read 2 more answers

The average score of this quiz is 24 points with a standard deviation of 1.5 points. What is the probability that someone scored

navik [9.2K]

Answer:

8.08 %

Step-by-step explanation:

Let us denote : $X=$ score X follows a normal distribution with mean $=24$ and standard deviation $=1.5$

Step 2

The probability that someone scored 21.9 or less is :

$\mathrm{P}(\mathrm{X} \leq 21.9)$

$=\mathrm{P}\left(\mathrm{Z} \leq \frac{21.9-24}{1.5}\right)$

$=\mathrm{P}(\mathrm{Z} \leq-1.4)$

$=0.0808$

$=8.08%$

Answer : $8.08 %$

7 0

3 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(X = 8) = 0.0037$

$P(X < 5) = 0.805$

$P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is $p = 0.267$

Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable X we have that

$X \ \ \~ \ \ { B ( p , n )}$

The probability distribution function for binomial distribution is

$P(X = x ) = ^nC_x * p^x * (1 -p) ^{n-x}$

Considering question a

Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as

$P(X = 8) = ^{12} C_8 * (0.267)^8 * (1- 0.267)^{12-8}$

Here C denotes combination

$P(X = 8) = 495 * 0.000025828 * 0.28867947$

$P(X = 8) = 0.0037$

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as

$P(X < 5 ) =[P(X = 0 ) + \cdots + P(X = 4)]$

=> $P(X < 5 ) =[ ^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0} + \cdots + ^{12} C_4 * (0.267)^4 * (1- 0.267)^{12-4} ]$

=> $P(X < 5 ) = 0.02406 + 0.10516 + 0.21067 + 0.25580 + 0.20964$

=> $P(X < 5) = 0.805$

Considering question c

Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

$P(X > 6) = 1 - p(X \le 6)$