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marysya [2.9K]
3 years ago
11

Find the slope of the line containing the points (0, 3) and (-6, 1)

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Step-by-step explanation:

To find the slope of any linear line you would have to use the formula \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }.

(-6 , 1) = (x_{2}, y_{2})

(0 , 3) = (x_{1}, y_{1})

Now you would insert the values into the formula....

\frac{1-3}{(-6)-0} = \frac{-2}{-6} = \frac{1}{3}

1/3 is your answer.

If you want to check your answer, you would use the formula mx + b= y

m= slope

x = the x-coordinate in either of the coordinates

b= the y-intercept

y = the y-coordinate of the coordinate you chose

mx +b = \frac{1}{3}(-6) +3 = -2 +3 = 1

1/3 is the correct answer

Hope this helps!!!

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At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperature is 50° Celsius. This
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Answer:

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Step-by-step explanation:

We are given that

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r=\frac{1}{5}/min

We have to find the function that gives the temperature difference in degrees Celsius D(t).

We know that

D(t)=a(1-r)^t

Substitute the values

D(t)=50(1-\frac{1}{5})^t=50(1-0.2)^t

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This is required function that gives the temperature difference in degrees Celsius.

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3 years ago
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mylen [45]
B and C are absurd; if a series converges, it must have a sum, but if a series diverges, it cannot have a sum.

Now, notice that

\dfrac12+\dfrac29+\dfrac4{27}+\dfrac8{81}+\cdots=\dfrac12+\dfrac{2^{2-1}}{3^2}+\dfrac{2^{3-1}}{3^3}+\dfrac{2^{4-1}}{3^4}+\cdots

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\dfrac12+\dfrac12\displaystyle\sum_{n=1}^\infty\left(\frac23\right)^n

The series is geometric with common ratio \dfrac23, so the series converges (and thereby has a sum), so the answer is D.
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Answer:

V ≈ 527.79

Step-by-step explanation:

Formula is V= πr2h

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