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Pani-rosa [81]
4 years ago
10

4. Kim took a test that had 20

Mathematics
1 answer:
gladu [14]4 years ago
8 0
75% of 20 is 15
so she got 5 incorrect x
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ch4aika [34]

Answer:

8 y^{50}

Step-by-step explanation:

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

\left(64 y^{100}\right)^{\frac{1}{2}}

Apply radical rule: \sqrt[n]{a}=a^{\frac{1}{2}} and a^{m+n}=a^m+a^n

\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}

Hence, 8 y^{50} is equivalent to  (64 y Superscript 100 Baseline) Superscript one-half.

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