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babymother [125]
3 years ago
12

Find the value of x and y

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Step-by-step explanation:

5x-17 and 3x-11 are supplementary angles

They add up to 180 degrees

5x-17 + 3x - 11 = 180

8x - 28 = 180

8x= 208

x= 26

3x-11, 90, and 2y + 5 added together equal 180

3x-11 + 90 + 2y + 5 = 180

3(26) - 11 + 2y + 5 = 90

78 - 6 + 2y = 90

72 + 2y = 90

2y = 18

y = 9

I hope this helps!!!

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andrey2020 [161]

Answer:

1). y = -7/5x - 4

2). y = 1/5x - 5

Step-by-step explanation:

In this question, we have to write the slope-intercept form of the given information.

Slope intercept form is: y = mx + b

Our "m" value is our slope and our "b" value is our y-intercept.

With that knowledge, we can plug in our given information to the slope-intercept equation:

1) slope = -7/5, y-intercept = -4

Plug -7/5 to "m" and -4 to "b"

y = -7/5x - 4

2) slope = 1/5, y-intercept = -5

Plug 1/5 to "m" and -5 to "b"

y = 1/5x - 5

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3 years ago
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B) x=2 and y=14 i’m pretty sure lol
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3 years ago
Which method could be used to factor x2 - 25?
Mandarinka [93]

Answer:

A. Perfect square Trinomial

Step-by-step explanation:

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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

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Answer:

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Step-by-step explanation:

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