Answer:
72 pi + 48 pi= 120pi (not sure if I am right tho)
Step-by-step explanation:
To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Step-by-step explanation:
Hey there!
While factorising you remember to make it take common in most of the expression.
Here;
=mx+cx+my+cy
Take common 'x' in "mx+cx" and 'y' in my + cy.
= x(m+c) + y(m+c)
Now, "(m+c)" common again.
= (m+c) (x+y)
Therefore the factorized form of the expression in (m+c)(x+y).
<u>Hope it helps</u><u>.</u><u>.</u><u>.</u>