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3 years ago

A city has 4 new houses for every 7 old houses. If there are 32 new houses in the city, how many old houses are there?

Mathematics

1 answer:

Maslowich3 years ago

3 0

So the ration is 4:7

The total of houses is 32 new houses. What I did was I divided 32 by 4:

32/4 = 8

That means that the ratio (4:7) would be multiplied by 8 (only the :7 part):

7 * 8 = 56

There are 56 old houses (the ratio is now 32:56)

Thank you and can you please give me brainly :3

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Answer:

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Step-by-step explanation:

GIVEN: The length of each side of a square is $3$ inches more than the length of each side of a small square. The sum of the areas of the square is $549$ inches.

TO FIND: the lengths of the sides of the two squares.

SOLUTION:

let the length of side of small square be $\text{x}$

Area of small square $=(\text{side})^2=\text{x}^2$

As length of each side of bigger square is $3\text{ inches}$ more than the smaller square

length of side of bigger square $=\text{x}+3\text{ inches}$

Area of bigger square $=(\text{x+3})^2$

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Sum of areas of both square $=549\text{ inch}^2$

$(\text{x})^2+(\text{x+3})^2=549$

$2\text{x}^2+6\text{x}+9=549$

$\text{x}^2+3\text{x}-270=0$

$\text{x}=15,-18$

as the length of side can never be negative

$\text{x}=15$

length of side of smaller square $=15\text{ inches}$

length of side of bigger square $=\text{x}+3\text{ inches}$ $=18\text{ inches}$

Hence the length of smaller and bigger square are $15\text{ inches}$ and $18\text{ inches}$ respectively.

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Answer:

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Step-by-step explanation:

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