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3 years ago

Help please The question is in the photo

Mathematics

2 answers:

KonstantinChe [14]3 years ago

8 0

I think 23 but we’re gonna need a clearer shot.

Sergio039 [100]3 years ago

5 0

I believe the answer to your question is 23

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Can someone help me with 2-89! Please

mr Goodwill [35]

Answer:

Step-by-step explanation:

A. 2x+3y+z

X = -2

Y= -3

Z= 5

2(-2)+3(-3)+5

-4-9+5

B. X-Y

-2–3

-2+3

C. 2(x+y/z)

2(-2-3/5)

2(-1)

=-2

D. 3x^2-2x+1

3(-2)^2-2(-2)+1

3(4)+4+1

=17

E.3y(x+x^2-y)

3(-3)(-2+-2^2-(-3))

-9(1)

=-9

F.-z^2(1-2x)/y-x

5^2(1-2(-2)/-3–2

25(5/5)

25(1)

=25

5 0

3 years ago

Solve the initial value problems.

slavikrds [6]

Both equations are linear, so I'll use the integrating factor method.

The first ODE

$xy' + (x+1)y = 0 \implies y' + \dfrac{x+1}x y = 0$

has integrating factor

$\exp\left(\displaystyle \int\frac{x+1}x \, dx\right) =\exp\left(x+\ln(x)\right) = xe^x$

In the original equation, multiply both sides by eˣ :

$xe^x y' + (x+1) e^x y = 0$

Observe that

d/dx [xeˣ] = eˣ + xeˣ = (x + 1) eˣ

so that the left side is the derivative of a product, namely

$\left(xe^xy\right)' = 0$

Integrate both sides with respect to x :

$\displaystyle \int \left(xe^xy\right)' \, dx = \int 0 \, dx$

$xe^xy = C$

Solve for y :

$y = \dfrac{C}{xe^x}$

Use the given initial condition to solve for C. When x = 1, y = 2, so

$2 = \dfrac{C}{1\cdot e^1} \implies C = 2e$

Then the particular solution is

$\boxed{y = \dfrac{2e}{xe^x} = \dfrac{2e^{1-x}}x}$

The second ODE

$(1+x^2)y' - 2xy = 0 \implies y' - \dfrac{2x}{1+x^2} y = 0$

has integrating factor

$\exp\left(\displaystyle \int -\frac{2x}{1+x^2} \, dx\right) = \exp\left(-\ln(1+x^2)\right) = \dfrac1{1+x^2}$

Multiply both sides of the equation by 1/(1 + x²) :

$\dfrac1{1+x^2} y' - \dfrac{2x}{(1+x^2)^2} y = 0$

and observe that

d/dx[1/(1 + x²)] = -2x/(1 + x²)²

Then

$\left(\dfrac1{1+x^2}y\right)' = 0$

$\dfrac1{1+x^2}y = C$

$y = C(1 + x^2)$

When x = 0, y = 3, so

$3 = C(1+0^2) \implies C=3$

$\implies \boxed{y = 3(1 + x^2) = 3 + 3x^2}$

7 0

2 years ago

Find an equation for the line that passes through the points (-4,-1) and (6,-5)

Sergio [31]

Answer:

y= -2/5x-13/5

Step-by-step explanation:

4 0

3 years ago

Math when is the sum of two negative mixed numbers an integer

FrozenT [24]

The short answer is: when their fractions add up to full integers.

For examples, two halves make up a whole, or

$\frac{1}{2} + \frac{1}{2}=1$

so the mixed numbers with those will add up to full integers:

$-12\frac{1}{2} + (-3\frac{1}{2})=(-(12+3+1)=-16$

but if they don't add up to an interger, the whole sum won't be an integer:

$-12\frac{3}{4} + (-3\frac{3}{4})=(-(12+3+1\frac{1}{2})=-16\frac{1}{2}$

5 0

3 years ago

In how many ways can the letters of the word POLICEMAN be arranged if the 'word' must begin with L and end with a vowel? & W

Vladimir79 [104]

Answer:

20160 ways

Probability = 0.0556

Step-by-step explanation:

We have 9 different letters, so the total number of words we can make is:

$Total = 9! = 362880\ words$

If we want just the words that begin with L and end with a vowel, we would have the first letter "locked", so we have 8 letters remaining, and it must end with a vowel, so the last "slot" has just 4 possible values (A, E, I or O). Then we would have 4 possible values for the last letter and 7 remaining letters in the middle of the word:

$N = 4 * 7! = 4*7*6*5*4*3*2 = 20160\ words$

The probability is calculated by the division of the number of words we want over the total number of words:

$P = N / Total = 20160 / 362880 = 0.0556$

5 0

3 years ago