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allochka39001 [22]
2 years ago
12

Hellppp meeeeeee PLEASEEEEE::::

Mathematics
2 answers:
lakkis [162]2 years ago
3 0
Fewer than 17 because 40 - 6 = 32 and 32 / 2 is 16
Citrus2011 [14]2 years ago
3 0

Step-by-step explanation:

Since each batch uses 2 cups of flour, he can only make 19 batches

6 cups of flour would make 3 batches

then 19-3 would give you 16

hence the answer is fewer than 17

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Please answer this question!! (Language)
stepan [7]
It is true, the predicate is the action part of a sentence. So the object or noun would be separated by a verb.
8 0
3 years ago
Each of the letters of the word ALABAMA are written on a piece of paper and then
Kruka [31]

Answer:

3/7

Step-by-step explanation:

There are 7 letters in ALABAMA. And there are 4 A's in ALABAMA. So if you're trying to not get an A then you would subtract 4 from 7. Which you would get 3/7 of the letters in ALABAMA are not A.

7 0
2 years ago
Solve: 3(5x - 8) = 6x + 39
soldier1979 [14.2K]

Steps to solve:

3(5x - 8) = 6x + 39

~Distribute left side

15x - 24 = 6x + 39

~Add 24 to both sides

15x = 6x + 63

~Subtract 6x to both sides

9x = 63

~Divide 9 to both sides

x = 7

Best of Luck!

6 0
3 years ago
Simplify. <br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7B44%7D" id="TexFormula1" title="\sqrt{44}" alt="\sqrt{44}" align="absm
zvonat [6]
The answer is 6.6
hope this helps :)
3 0
3 years ago
Given a focus of (4, 5) and directrix of y= -3 , find the equation of the parabola.
andrey2020 [161]
Check the picture below.

notice, the focus point is at 4,5 whilst the directrix line is at y = -3, below the focus point, meaning the parabola is vertical and opening upwards.

keeping in mind that the vertex is "p" distance from either of these fellows, then the vertex is half-way between both of them, notice in the picture, the distance from y = 5 to y = -3 is 8 units, half that is 4 units, thus the vertex 4 units from the focus or 4 units from the directrix, that puts it at (4,1), whilst "p" is 4, since the parabola is opening upwards, is a positive 4 then.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;(y-{{ k}})^2=4{{ p}}(x-{{ h}})&#10;\\\\&#10;\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=4\\&#10;k=1\\&#10;p=4&#10;\end{cases}\implies (x-4)^2=4(4)(y-1)\implies (x-4)^2=16(y-1)&#10;\\\\\\&#10;\cfrac{1}{16}(x-4)^2=y-1\implies \cfrac{1}{16}(x-4)^2+1=y

8 0
3 years ago
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