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vodomira [7]
4 years ago
13

Can someone please help with these other 2

Mathematics
1 answer:
ikadub [295]4 years ago
3 0

Part b:

f(a+3)=(a+3)^2+4

Solve for (a+3)^2

= (a^2+2(3)(a)+3^2)+4

= a^2+6a+13

Part c:

f(d+b)=(d+b)^2+4

Solve for (d+b)^2

= (d^2+2db+b^2)+4

= d^2+2db+b^2+4

Let me know if you need any clarifications, thanks!

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Find the LCm for the pair of natural numbers <br> 112,96
n200080 [17]

Answer:

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Step-by-step explanation:

First find the prime factors:

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96 = 2*2*2*2*2*3

There are 4 pairs of duplicate 2 's  in the factors, so the LCM = 2*2*2*2*2*3*7

= 672 (answer).

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3 years ago
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(c) Write these fractions in order of size.
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3 years ago
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3 0
3 years ago
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Hope this helps!
6 0
3 years ago
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