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oksano4ka [1.4K]
3 years ago
7

Q7 Q22.) How far is the ball from the center of the​ green?

Mathematics
2 answers:
Drupady [299]3 years ago
6 0

{c}^{2}  =  {a}^{2}  +  {b}^{2} - 2ab \cos(c)  \\  {x}^{2}  = {130}^{2}  +  {25}^{2}  - 2(130)(25) \cos(105)  \\ {x}^{2} = 16900 + 625 - 6500 \cos(105)  \\  {x}^{2}  = 17525 + 1682.3 \\  {x}^{2}  = 19207.3 \\ x =  \sqrt{19207.3}  \\ x = 138.59

Answer : 138.6 yards after rounding off

Hope this helps. - M
BARSIC [14]3 years ago
5 0
See the attached picture:

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Multiply.<br>(2x-5) (3x-7)​
Naya [18.7K]

Answer:

6x^2 -29 +35.

Step-by-step explanation:

use the FOIL method(First, Outer,Inner, and Last.)

2x x 3x=6x^2.

2x x -7=-14x.

-5 x 3x =-15x.

-5 x -7=35.

= 6x^2 -14x -15x+35

6x^2 -29x +35.

4 0
3 years ago
The roots of x2 -( ) +34 are 5 -/+3i
asambeis [7]

Answer: 10

Step-by-step explanation:

Vieta's formulas :

5 - 3i + 5 + 3i = b ⇒ b =10

Now, we have the equation:

x² -10x + 34 = 0

Mark me brainliest

7 0
3 years ago
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Step2247 [10]

Answer:

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6 0
3 years ago
The whole numbers from 10-12 are paired with their factors explain why this pairing doesnt describe a function
myrzilka [38]

Answer:

As given whole numbers from 10 - 12 are paired with their factors.

factor of ,10=1,2,5,10 → (10,1),(10,2),(10,5)(10,10)

factor of 11=1, 11 → (11,1),(11,11)

factor of 12=1,2,3,4,6,12→ (12,1),(12,2),(12,3),(12,4),(12,6),(12,12)

As we know for an ordered pair to be function Every element in the domain must have a unique image, i.e it can't have more than one image.

→ As element 10, have four images,which are 1,2,5,10 so it can,t be a function.

Similarly element 11 have two images 1,11 so it can't be a function.

Element 12 have six images 1,2,3,4,6,12, so it also can't be written as function.





8 0
3 years ago
Which expression is the completely factored form of x6−64y3 ?
ss7ja [257]

We are given this

x^6 -64y^3

write it as the difference of cubes

(x^2)^3 -(4y)^3

use the formula for the difference of cubes

(x^2-4y) ((x^2)^2+x^2*4y+(4y)^2)

Now use the formula for the difference of squares as 4y = (2\sqrt{y} )^2

(x-2\sqrt{y}) (x+2\sqrt{y}) (x^4+4x^2y+16y^2)

7 0
3 years ago
Read 2 more answers
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