Ask question

Ask question

All categories

oksano4ka [1.4K]

3 years ago

7

Q7 Q22.) How far is the ball from the center of the green?

2 answers:

Drupady [299]3 years ago

6 0

${c}^{2} = {a}^{2} + {b}^{2} - 2ab \cos(c) \\ {x}^{2} = {130}^{2} + {25}^{2} - 2(130)(25) \cos(105) \\ {x}^{2} = 16900 + 625 - 6500 \cos(105) \\ {x}^{2} = 17525 + 1682.3 \\ {x}^{2} = 19207.3 \\ x = \sqrt{19207.3} \\ x = 138.59$

Answer : 138.6 yards after rounding off

Hope this helps. - M

BARSIC [14]3 years ago

5 0

See the attached picture:

You might be interested in

The triangles are similar. The area of the larger triangle 603cm2. what is the area of the smaller triangle?

tekilochka [14]

The smaller triangle is scaled by a factor of (18 cm)/(54 cm) = 1/3 of the larger triangle. The ratio of areas is the square of that scale factor.

small triangle area = (1/3)^2 × large triangle area

... = (1/9) × 603 cm^2

... = 67 cm^2

The appropriate choice is

... C. 67 cm^2

6 0

3 years ago

The number of students that enrolled in a new school club as a function of time can be represented by the function as shown in t

madam [21]

Answer:

I think it is 1 student per 15 min

Step-by-step explanation:

5 0

3 years ago

Use the favorite game picture graph to answer the question

Novay_Z [31]

Answer:

There's no question-

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Consider the logarithmic function f(x) = log10(x).

disa [49]

$log_{10} 50=1.70$

3 0

3 years ago

Read 2 more answers

What is the sum of the infinite geometric series?<br><br> 120 + 20+ 10/3 + 5/9+...

Sergeu [11.5K]

Answer:

for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

$\frac{a_{1} }{1 - r}$ = $\frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } =$ $\frac{120 \times 6}{5}$ = 144.

Step-by-step explanation:

i) from the given series we can see that the first term is $a_{1 }$ = 120.

ii) let the common ratio be r.

iii) the second term is 20 = 120 × r

therefore r = 20 ÷ 120 = $\dfrac{1}{6}$

iv) the third term is $\frac{10}{3}$ = 20 × r

therefore r = $\dfrac{10}{3}$ ÷ 20 = $\dfrac{1}{6}$

v) for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

$\frac{a_{1} }{1 - r}$ = $\frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } =$ $\frac{120 \times 6}{5}$ = 144.

6 0

3 years ago