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nikitadnepr [17]
3 years ago
14

An electron jumps down from the fourth energy level to the first energy level and releases a light wave of 10.8 nm in wavelength

. Determine the energy level value for the fourth energy level for the atom
Chemistry
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

-20.2  * 10^-18 J

Explanation:

From;

E = hc/λ

h= planks constant = 6.6 * 10^-34 Js

c= speed of light = 3 * 10^8 ms-1

λ = wavelength = 10.8 * 10^-9 m

Substituting values;

E = 6.6 * 10^-34 * 3 * 10^8/ 10.8 * 10^-9

ΔE = -1.8 * 10^-17 J

But for ground state  E1=−13.6eV or -2.176 * 10^-18 J

From;

ΔE = E4 - E1

E4 = ΔE + E1

E4 =  (-1.8 * 10^-17) + (-2. 176* 10^-18)

E4 = -20.2  * 10^-18 J

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Titration Volume &amp; Concentration
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18,1 mL of a 0,304M HCl solution.

Explanation:

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By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:

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