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Sholpan [36]
3 years ago
8

Find the maximum mass of MgO that can be made from 2.4 of Mg and 2.4 of O2

Chemistry
1 answer:
Yanka [14]3 years ago
3 0
Need more information
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a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?
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Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

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Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

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Molarity = 45.33/100 = 0.4533mol/L

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