12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
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13.04, 13.06, 13.4, 13.6, 13.12
I think that’s right
The total surface area of the triangular prism that has a height of h and the side length of a is given below.
![\rm a(\dfrac{\sqrt3}{2} \ a + 3h)](https://tex.z-dn.net/?f=%5Crm%20a%28%5Cdfrac%7B%5Csqrt3%7D%7B2%7D%20%5C%20a%20%2B%203h%29)
<h3>What is a triangular prism?</h3>
A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.
A box is in the shape of an equilateral triangular prism.
If the box is to be covered with paper on its lateral sides.
Let a be the side length of the equilateral triangle and h be the height of the prism.
Then the surface area of the triangular prism will be
Surface area = 2 × area of triangle + 3 × area of the rectangle
The area of the triangle will be
![\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}](https://tex.z-dn.net/?f=%5Crm%20Area%5C%20of%5C%20triangle%20%3D%20%5Cdfrac%7B%5Csqrt%7B3%7Da%5E2%7D%7B4%7D)
The area of the rectangle will be
![\rm Area \ of \ rectangle = a \ h](https://tex.z-dn.net/?f=%5Crm%20Area%20%5C%20of%20%5C%20rectangle%20%3D%20a%20%5C%20h)
Then the total surface area will be
![\rm Surface\ area = 2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area = a(\dfrac{\sqrt3}{2} \ a + 3h)](https://tex.z-dn.net/?f=%5Crm%20Surface%5C%20area%20%3D%20%202%20%5Ctimes%20%5Cdfrac%7B%5Csqrt3%20a%5E2%20%7D%7B4%7D%20%2B%203%20ah%5C%5C%5C%5C%5C%5CSurface%5C%20area%20%3D%20%20a%28%5Cdfrac%7B%5Csqrt3%7D%7B2%7D%20%5C%20a%20%2B%203h%29)
More about the triangular prism link is given below.
brainly.com/question/21308574
The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <=
![4 \sqrt{7}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B7%7D%20)
W <=
![\frac{4 \sqrt{7} }{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20%5Csqrt%7B7%7D%20%7D%7B3%7D%20)
cm