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Minchanka [31]
3 years ago
15

Lines a and b are parallel. line c is perpendicular to both line a and line B. Which statement about lines a,b and C is not true

?

Mathematics
2 answers:
7nadin3 [17]3 years ago
7 0

When lines are parallel, they have the same slope, so the statement "line a and line b have the same slope" is TRUE


When lines are perpendicular, the slopes are opposites (the sign and number is flipped)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -1

perpendicular line's slope is 1/1 or 1

slope is 4/5

perpendicular line's slope is -5/4


When you multiply(the product) perpendicular slopes together, they equal -1. Since line c is perpendicular to line a and line b, the product of their slopes is -1.(so this is true)


The statement "the sum of the slopes of line a and b is 0" is false because if they have the same slope, when added together the result would not be 0. The slopes of line a and line b is -2/3, so the sum would be -4/3.

Paha777 [63]3 years ago
7 0

Answer:

Option A) The sum of slopes of a and b is zero

Step-by-step explanation:

We are given the following:

Line ~a \parallel Line ~b

Line ~c \perp Line ~a\\Line ~c \perp Line ~b

We have to find the false statement.

a) The sum of slopes of a and b is zero

The given statement is false as the parallel lines have same slope and their sum can only be zero if the slopes of both the parallel lines is zero.

b) Lines a and b have same slope

The statement is true. Parallel lines have same slope.

c) The product of slopes of line a and line c is -1

The statement is true.

As two perpendicular lines with slope m_1, m_2 respectively, satisfies the property:

m_1 \times m_2 = -1

d) The product of slopes of line b and line c is -1

The statement is true.

Again, as two perpendicular lines with slope m_1, m_2 respectively, satisfies the property:

m_1 \times m_2 = -1

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What is 8,000,000 + 100,000 + 7,000 + 400 + 20 + 4 in standard form?
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What is the quotient when 4x3 + 2x + 7 is divided by x + 3?
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The quotient of this division is (4x^2 -12x + 38). The remainder here would be -26.

Step-by-step explanation:

The numerator 4x^3 + 2x + 7 is a polynomial about x with degree 3.

The divisor x + 3 is a polynomial, also about x, but with degree 1.

By the division algorithm, the quotient should be of degree 3 - 1 = 2, while the remainder shall be of degree 1 - 1 = 0 (i.e., the remainder would be a constant.) Let the quotient be a\,x^2 + b\, x + c with coefficients a, b, and c.

4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3).

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is 4 x^3. On the right-hand side, that would be a\, x^3. Hence a = 4.

Now, given that a = 4, rewrite the right-hand side:

\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}.

Hence:

4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)

Subtract \left(4x^3 + 12x^2\right from both sides of the equation:

-12x^2 + 2x + 7 = (b\,x + c)(x + 3).

The term with a degree of two on the left-hand side has coefficient (-12). Since the only term on the right hand side with degree two would have coefficient b, b = -12.

Again, rewrite the right-hand side:

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Subtract -12x^2 -36x from both sides of the equation:

38x + 7 = c(x + 3).

By the same logic, c = 38.

Hence the quotient would be (4x^2 - 12x + 38).

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