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Svetradugi [14.3K]
2 years ago
11

Which is the Best Buy

Mathematics
1 answer:
nasty-shy [4]2 years ago
8 0
Last one for sure it should be right
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Reduce to simplest form. -\dfrac{1}{3}-\left(-\dfrac{3}{5}\right)=− 3 1 ​ −(− 5 3 ​ )=minus, start fraction, 1, divided by, 3, e
nevsk [136]

Answer:

-1/3 - (-3/5) = 4/15

Step-by-step explanation:

Reduce to simplest form

-1/3 - (-3/5)

= -1/3 + 3/5

Find the Lowest Common Multiple of 3 and 5

Lowest Common Multiple of 3and 5 is 15

Use the LCM to Simplify

= {(-5*1)+(3*3)} / 15

= (-5+9) / 15

= 4/15

Therefore,

-1/3 - (-3/5) = 4/15

7 0
2 years ago
Read 2 more answers
In sale the normal price is reduced by 10% Nathalie bought a pair of shoes in the sale of 54 whats the original price
Sholpan [36]
$59.40 was the original price for the shoes

5 0
3 years ago
In △ABC the points M and N belong to the sides
tangare [24]

Try this solution, it consists of two parts (MN=8).

4 0
3 years ago
Identify the equation for the parabola with vertex (0, 0) and directrix x = 2.5.
GREYUIT [131]

Answer:

jk

Step-by-step explanation:

8 0
3 years ago
Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
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