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3 years ago

What is 75:___= 25:8

Mathematics

2 answers:

AnnZ [28]3 years ago

8 0

Answer:

Step-by-step explanation:

Considering that 25 can go into 75 by being multiplied by 3, you'd multiply 8 by 3 to get your answer.

vova2212 [387]3 years ago

3 0

Answer:

Step-by-step explanation:

75/3 is equal to 25... So, in theory, if you multiply 8 by 3, you should get 24. To check that: 75/24 = 25/8

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A number a is to the left of the number b on the number line how do the numbers -a and -b compare?

Leokris [45]

Answer:

-a will be greater than -b because for example, when a=2 and b=5, -a=-2 and -b=-5

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2 years ago

Solve <br> 36+12v+9v=-3v-36

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Answer:

V=4

Step-by-step explanation:

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3 years ago

67% of owned dogs in the United States are spayed or neutered. Round your answers to four decimal places. If 48 owned dogs are r

oksian1 [2.3K]

Answer:

a) Probability that exactly 29 of them are spayed or neutered = 0.074

b) Probability that at most 33 of them are spayed or neutered = 0.66

c) Probability that at least 30 of them are spayed or neutered = 0.79

d) Probability that between 28 and 33 (including 28 and 33) of them are spayed or neutered = 0.574

Step-by-step explanation:

This is a binomial distribution question

probability of having a spayed or neutered dog, p = 0.67

probability of having a dog that is not spayed or neutered, q = 1 - 0.67

q = 0.23

sample size, n = 48

According to binomial distribution formula:

$P(X=r) = nCr p^r q^{n-r}$

where $nCr = \frac{n!}{(n-r)! r!}$

a) Probability that exactly 29 of them are spayed or neutered

$P(X= 29) = 48C29 * 0.67^{29} * 0.23^{19}\\P(X=29) = 0.074$

b) Probability that at most 33 of them are spayed or neutered

$P(X \leq 33) =1 - P(X > 33)\\P(X \leq 33) =1 - 0.34\\P(X \leq 33) = 0.66$

c) Probability that at least 30 of them are spayed or neutered

$P(X \geq 30) = 1 - P(x < 30)\\P(X \geq 30) = 1 - 0.21\\P(X \geq 30) = 0.79$

d) Probability that between 28 and 33 (including 28 and 33) of them are spayed or neutered.

$P(28 \leq X \leq 33) = P(X=28) + P(X=29) + P(X=30) + P(X=31) + P(X=32) + P(X=33)\\P(28 \leq X \leq 33) = 0.053 + 0.074 + 0.095 + 0.112 + 0.121 + 0.119\\P(28 \leq X \leq 33) = 0.574$

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3 years ago

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Elenna [48]

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3 years ago

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2/3 employees of a company drive to work, 1/3 travel by bus and the rest walk . find the number of who walk.

olasank [31]

Zero
2/3 drive plus 1/3 bus = 3/3 or 1 whole
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2 years ago