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Katyanochek1 [597]
3 years ago
11

Al predicted that he would sell 220 hot dogs at lunch time. When the hot dogs ran out, 35 people were still waiting in line to b

uy hot dogs. What was the percent error in the estimate? Round the answer to the nearest tenth. ∵
Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0
Assuming 1 hot dog per person, the error was
.. (220/(220 +35) -1)*100% = -13.7%

Al's prediction was 13.7% low.
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3 years ago
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7 0
3 years ago
I'm in need of help please
lidiya [134]
First, the graph is a parbole, this is a square function, so it can not be the option a) because it is a linear function.

Second, the vertix of the parabole is the point (0,3), so use the general vertex form of the parabole:

y = A(x - h)^2 + k, where h and k represent the vertex (h,k).

So, the form of the funtion is y = A (x-0)^2 - 3 = Ax^2 - 3

Now, you also know that the roots of the parabole are close to -1 and 1 but they are not those exact value.

So, find the roots for any of the possible options:

b) f(x) = 2x^2 - 3 = 0 => 2x^2 = 3 => x^2 = 3/2 => x = +/- √(3/2) ≈ +/- 1.22

That is a very plausible answer

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3) f(x) = x^2 - 3 = 0 => x^2 = 3 => x = +/- √3 ≈ +/- 1.73, which is not so close to +/- 1.

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