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Alex_Xolod [135]
3 years ago
9

Which statement best describes the excluded values of a rational expression?

Mathematics
2 answers:
kvv77 [185]3 years ago
8 0
<h2>Answer:</h2>

Option: B is the correct answer.

B.  The number of excluded values of a rational expression cannot exceed the degree of the denominator.

<h2>Step-by-step explanation:</h2>

We know that a rational expression is a expression of the form:

\dfrac{p(x)}{q(x)}

where p(x) and q(x) are polynomials.

Excluded value--

The excluded value of a rational expression are the values where the denominator of the expression is zero.

Also, the number of zeros of a polynomial is always less than or equal to degree of the polynomial.

Hence, the  number of excluded values of a rational expression cannot exceed the degree of the denominator.

         The answer is:

            Option: B

denis23 [38]3 years ago
3 0
 the answer is b because
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Goshia [24]

Answer:

C: (x^2+4)^2

Step-by-step explanation:

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3 years ago
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wlad13 [49]
<span>Solve the system

9x = 27-9y
20x=71-9y

Let's use the "elimination through addition/subtraction method.
Multiply the first equation by -1 so as to obtain +9y:

-9x = -27 + 9y
</span><span>20x=  71-   9y
--------------------

Add these 2 equations together:

</span>-9x = -27 + 9y
20x=  71-   9y
--------------------
<span> 11x = 44

Solve this for x:  x = 44/11 = 4.

Now find y by subst. 4 for x in either of the original equations.

Using the second equation:    </span><span> 

</span>20x=71-9y
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80-71 = -9y
9 = -9y.  Then y = -1.

The solution set is (4,-1).
7 0
3 years ago
Find the simplest pattern and insert the missing term(s) of each sequence. 4, 7, 12, 21, 38, ___
Arte-miy333 [17]

Answer:

71

Step-by-step explanation:

4, 7, 12, 21, 38, ...

  • 2+2=2¹+2
  • 4+3= 2²+3
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next term:

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Answer:

I am stuck on this problem too. Is it on eacxt path.

Step-by-step explanation:

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2 years ago
Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?
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Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>

⇒ NO || KL and NO = \frac{1}{2}KL

Therefore segment NO is parallel to the segment KL.

6 0
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