Answer:
The length of the rectangle is 9 cm
Step-by-step explanation:
Given: The length of rectangle(l) = (x+3) cm and a width of rectangle (w) = 
cm a
Also, perimeter of rectangle is 24 cm.
Perimeter of rectangle is to add the lengths of all the four sides.
Perimeter of rectangle (P) is given by;
P=2(l+w)
Substituting the value of P = 24 cm , l = (x+3) cm and w =
then,
Divide by 2 both sides of an equation;
Combine like terms;
Subtract 3 from both the sides we get;
Simplify:
Multiply both sides by 
we get
Therefore, length of rectangle(l) = (x+3) = 6+3 = 9 cm
Answer:
x=12
Step-by-step explanation:
First you make sure x is on both sides of the equation. So you do 0.7x-5-0.2x=0.2x+1-0.2x. Which just simplifies to 0.5x-5=1. You make sure x is the only thing on that side of the equation so you do 0.5x-5+5=1+5 which simplifies to 0.5x=6. Multiply the equation times 2 to just have x. x=12. The value that makes true of x is 12.
15/2 = $7.5 per hour
7.5 times 5 = $37.50 earned in 5 hours
Hey there! :)
Answer:
Domain: (-∞, ∞)
Range: [-1, ∞)
Step-by-step explanation:
This is an absolute-value function. (Graphed below) The vertex is at (-3, -1) which consists of the minimum y-value of the function. Therefore:
Domain: (-∞, ∞)
Range: [-1, ∞)
I thought this would be simple, as I'm familiar with algebra and not really "The constant of proportionality," but I will do my best.
So this said "Constant of proportionality," is referring to basically the answers for the equation when X equals certain numbers.
Make a table of different answers when you plug in X and you get the 'Constant of proportionality.'
y = 2.5x + 3
y = 2.5(1) + 3
y = 2.5 + 3
y = 5.5
Since we plugged in 1 for X and got 5.5 for Y, our input and output is (1, 5.5)
Replace X for a different value, and you will get a bunch of different numbers that will in essence be your function inputs and outputs. Make a table of these and you have your answer.
EXAMPLE -
-= x =- -= y =-
-= 1 =- -= 5.5 =-
-= 2 =- -= 8 =-
-= 3 =- -= 11.5 =-
-= 4 =- -= 13 =-
So there you have it. I hope this helps! If you have any further questions, don't hesitate to ask.
