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solong [7]
3 years ago
7

I can find the common denominator of fractions with unlike denominators.

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

C. Disagree

<h2><u>HOPE IT HELPED</u></h2>

Step-by-step explanation:

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Can someone plss help ASAP
Elza [17]

Answer:

8.2.69 ≤ x ≤ 17.31

11. x-7.31 ≤ 10

12. x≤17.31

Let the amount in the other Piggybank be x.

If positive;

x-7.31 ≤ 10

x ≤ 10+7.31

x ≤ 17.31

If negative

-(x-7.31) ≤ 10

-x+7.31 ≤ 10

-x ≤ 10-7.31

-x ≤ 2.69

Multiply both sides by -1

x ≥ -2.69

The compound inequality representing the amount of money in the other bank is -2.69≤x≤17.31

Step-by-step explanation:

4 0
2 years ago
Suppose that, in an experimental setting, 100 students are asked to choose between Gamble A and Gamble B, where: Gamble A: The s
Stolb23 [73]
<h3>Answer: $2600</h3>

Focus on Gamble B only. Multiply each winnings with their corresponding probabilities.

5100*0.50 = 2550

200*0.25 = 50

0*0.25 = 0

Add up those results: 2550+50+0 = 2600

The expected value of gamble B is $2600

4 0
3 years ago
IF A, B, C are three mutually exclusive events with 1/3p(A)=2/3p(B)=1/6P(C).
Bas_tet [7]
A=2(67.76).45 it’s ten divided by 8
7 0
2 years ago
Rewrite the expression as a sum of terms, where each term is in the form k\cdot a^nk⋅a
muminat

Answer:

  2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}

Step-by-step explanation:

It looks like you want to expand the expression ...

  \sqrt{a}\left(2a^2 -\dfrac{4}{a}\right)

Use the distributive property and rules of exponents.

  =2a^{(\frac{1}{2}+2)}-4a^{(\frac{1}{2}-1)}\\\\=\boxed{2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}}

_____

The relevant rules of exponents are ...

  √a = a^(1/2)

  1/a = a^-1

  (a^b)(a^c) = a^(b+c)

8 0
3 years ago
Look at the screenshot-- help?
tatyana61 [14]
The last one is correct
3 0
3 years ago
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