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Verizon [17]
3 years ago
5

I need help how to solve it mot the answer plz and thank u

Mathematics
2 answers:
jek_recluse [69]3 years ago
4 0
The second one would be the answer. You want to plug in for this question. You can divide over the five leaving you with (x-2)^2 =25. Since you are squaring this answer, you want to get either 5 or negative five. Both -3 and 7 will do that.
Tatiana [17]3 years ago
4 0
(x-2) ^2 = 125/5,
from formula (a-b)^2= a^2 - 2ab+ b^2
the equation becomes
x^2 - 4x+4= 25
x^2-4x-21= 0
x^2 -7x+3x-21=0
x(x-7)+3(x-7)= 0
(x+3) (x-7)= 0
so either x+3=0
or x-7=0
x can have values x= -3, 7
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1.)
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Have a good night :)
5 0
3 years ago
Pls i cannot fail this !
FrozenT [24]
A= 3.14* 12^2
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3 0
2 years ago
Read 2 more answers
Factor and find the zeros of the relation.
Nady [450]

Answer:

Step-by-step explanation:

c.

y= 30x² +44x +16

factor

y= 2 (15x² +22x +8)

find zeros

15x²+22x+8=0

ax²+bx+c=0

x= (-b±√(b²-4ac))/2a

x= -22±√484-480/30 = -22±2/30 = -11±1/15

there are 2 zeros x= -10/15 ; x= -12/15

d.

y= 10x² +60x +80

factor

y= 10(x²+6x+8) = 10( x+2)(x+4)

finding zeros

x+2 =0 so x= -2

x+4 =0 so x= -4

there are 2 zeros x= -2; x= -4

4 0
3 years ago
Given EG = 16 and FH = 12, what is the length of one side
pav-90 [236]
8 is the answer cuz if you dive and all that
6 0
3 years ago
Read 2 more answers
____PLEASE HELP____
Dafna1 [17]

Answer:

I think its C!! but not sure

3 0
2 years ago
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