I need help how to solve it mot the answer plz and thank u

Mathematics

2 answers:

jek_recluse [69]2 years ago

4 0

The second one would be the answer. You want to plug in for this question. You can divide over the five leaving you with (x-2)^2 =25. Since you are squaring this answer, you want to get either 5 or negative five. Both -3 and 7 will do that.

Tatiana [17]2 years ago

4 0

(x-2) ^2 = 125/5,
from formula (a-b)^2= a^2 - 2ab+ b^2
the equation becomes
x^2 - 4x+4= 25
x^2-4x-21= 0
x^2 -7x+3x-21=0
x(x-7)+3(x-7)= 0
(x+3) (x-7)= 0
so either x+3=0
or x-7=0
x can have values x= -3, 7

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Step-by-step explanation:

You should prolly subtract 2 from both sides first.

So you get, -|2/5x + 3| > -1 2/5

Add three to both sides
-|2/5x| = -1 2/5
Do -1 and 2/5 divided by 2/5 to get -3.5, x > -3.5

One of the answers is x > -3.5 but you need to switch the sign to less than and make the other side the opposite.

$-( \frac{2}{5}x + 3 ) < 1 \frac{2}{5}$

You see that, switched the sign and made whats on the right side opposite. So now solve for x again but with this new equation. Also, the parentheses are absolute value signs

Subtract 3 from both sides

-|2/5x| < -1 and 3/5

Divide 2/5 from each side to get x < -4

I hope I'm correct, my bad if I'm wrong