1) √3 √7 = √21
2) √5 √245 = √5 √5 * 49 = √5 * 7√5 = 7 √5 * 5 = 7 √25 = 7 * 5 = 35
3) √77 ÷ √11 = as is. can't be simplified.
4) (√59)² = 59 ; the square root was cancelled by squared.
5) 3√6 x 8√7 = 3 * 8 √6 * 7 = 24 √42
6) 5√3 x 6 √3 = 5 * 6 √3 * 3 = 30 √9 = 30 * 3 = 90
7) 40√30 ÷ 5√3 = (40 / 5) * (√30 /√3) = 8 * ((√3 *10) / √3) = 8 √10
8) (6√5)² = 6² * √5² = 36 * 5 = 180
The probability that at most 8 of them take the bus to school is 0.925, written in percentage form this is 92.5%
<h3>
How to find the probability?</h3>
We know that roughly 75% of the students take the bus, then, if we select a student at random.
- There is a probability of 0.75 that the student takes the bus.
- There is a probability of 0.25 that the student does not take the bus.
The probability that at most 8 out of 9 students take the bus, is equal to one minus the probability of the 9 taking the bus, which is:
p = (0.75)^9 = 0.075
Then we have:
P = 1 - 0.075 = 0.925
The probability that at most 8 of them take the bus to school is 0.925, written in percentage form this is 92.5%
If you want to learn more about probability, you can read:
brainly.com/question/251701
Answer:
x = 28
Step-by-step explanation:
If AB and CD are the straight lines, sum all the angles formed at a point lying on this line will be 180°.
m∠COE + m∠EOF + m∠FOB + m∠BOD = 180° [Angles at a point O on line AB]
3x + x + (x + 12) + m∠BOD = 180°
m∠BOD = 180° - (5x + 12)
Similarly, m∠AOD + m∠AOC = 180°
152° + m∠AOC = 180°
m∠AOC = 28°
Since, ∠AOC and ∠BOD are the vertical angles,
m∠AOC = m∠BOD
180° - (5x + 12)° = 28°
5x + 12 = 180 - 28
5x = 140
x = 28
Find the area A of polygon CDEFGH with the given vertices. C(0,5), D(2,5), E(2,3), F(3,2), G(-1,2), H(0,3)
enot [183]
Answer:
<em>The area of the polygon CDEFGH is 7</em>
Step-by-step explanation:
<u>Area of a Polygon</u>
The area of a polygon is generally calculated as the sum of the smaller areas that form its full shape, give each partial area has a known shape, like a square, rectangle, triangle, circle, etc.
The six points given in the question are plotted in the image below. They form a polygon whose area can be divided into two smaller shapes:
The area CDHE is a square of length side 2. Area of a square:
The area HEFG is a trapezoid with bases lengths 4 and 2, and height 1. Area of a trapezoid:
Calculate both areas:
Total Area=4+3=7
The area of the polygon CDEFGH is 7
