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Fiesta28 [93]
3 years ago
6

[50 points... Will give brainliest] Explain how natural selection is impacted by genetic differences, variation, and survival.​

Biology
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Because natural selection acts directly only on phenotypes, more genetic variation within a population usually enables more phenotypic variation. Some new alleles increase an organism's ability to survive and reproduce, which then ensures the survival of the allele in the population.

Natural selection is the process through which populations of living organisms adapt and change. Individuals in a population are naturally variable, meaning that they are all different in some ways. This variation means that some individuals have traits better suited to the environment than others.

Natural selection is a mechanism of evolution. Organisms that are more adapted to their environment are more likely to survive and pass on the genes that aided their success. This process causes species to change and diverge over time.

I changed it a lot Mark me as brainliest!

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Pseudomonas putida is used for fermentation of the lactose present in cheese whey. The bacteria are cultivated in a steady-state
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Answer:

Explanation:

Given that:

The dilution rate D = 0.28 h⁻¹

The concentration of lactose in the feed S_o = 2.0 \ g/L

The effluent S = 0.10 g/L

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Y_{X/S} = 0.45 g\  X/g  \ S , \\ \\  Y_{X/O2  }= 0.25 g  \ X/g  \ O2,  \\ \\

Saturation C* = 8 mg/l

To calculate the steady-state biomass, we use the formula:

X = Y_{X/S}(S_o-S_e) \\ \\ X = 0.45(2.0 -0.10) \ g/L \\ \\ X= 0.45 (1.9) \ g/L \\ \\  X = 0.855\ g/L \\ \\  X = 855 \ mg/L

The biomass is 0.855 g/L

For a steady-state condition, the oxygen uptake rate can be illustrated by using the formula:

q_{o_2}X =\dfrac{\mu_X}{Y_{X/O_2}}

where;

\mu = dilution rate (D)

Thus, the steady-state can be expressed as:

q_{o_2}X =\dfrac{D}{Y_{X/O_2}}

q_{o_2}X =\dfrac{0.28}{0.25}

q_{o_2}X =1.12 \ h^{-1}

The specific rate of oxygen consumption q_{o_2}X =1.12 \ h^{-1}

b)

In the fermentation medium, if the desired DO concentration C_L = 2 mg/L

Here, the oxygen transfer is regarded as the rate-limiting step.

As such, the oxygen transfer rate(OTR) is equivalent to the oxygen uptake rate.

In this scenario, let's determine the oxygen transfer coefficient (K_{La}) by using the formula:

OTR =  K_{La}(C^* - C_L)

where;

K_{La}= coefficient of oxygen transfer

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Since OTR = q_{O_2}X

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Thus, the oxygen transfer coefficient K_{La} = 159.6 h⁻¹

4 0
3 years ago
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