The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
Step-by-step explanation:
Next time, please share the possible answer choices.
a^2 - b^2 is "a difference with two terms."
So is x - y.
Answer:
The answer is 118.
Step-by-step explanation:
First we need to subtract the meal cost from average unit cost for each meal:
A restaurant profits 1.25$ for each meal. If we divide fixed cost to profit for each meal:
The restaurant have to sell 118 meals at least each day for the owner to break even
Answer:
30% percent profit
Step-by-step explanation:
100 pence in a pound.
1000 grams in a kilogram.
She bought 5000g of sweets.
She pays 10×100=1000 pence.
She put them into 5000÷250=20 bags.
She sells the bags for 65 pence each.
She sells them all for 20×65=1300 pence.
She gets a profit of 300 pence or 3 pounds.
She gets a percent profit of 30%.
9 a
------ = -----
a 5
a^2 = 45
a = 3<span>√5
</span>
4 b
------ = -----
b 5
b^2 = 20
b = 2√5
answer:
a = 3√5
b = 2√5
hope it helps
