4 years ago

Simplest form of 6×/15×

Mathematics

1 answer:

docker41 [41]4 years ago

3 0

2/5
I belive that’s the answer

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A rectangle has width (2x + 3) and length (2x - 4). What is the perimeter of the<br> rectangle?

motikmotik

Answer:

8x-2

Step-by-step explanation:

perimeter=2l+2w

perimeter= 2(2x+3)+2(2x-4)

=4x+6+4x-8

=8x-2

6 0

4 years ago

Select the correct answer from each drop down menu

Illusion [34]

Answer:

1. 2 2. 1 3.(2,1)

Step-by-step explanation:

y=_x+3

plug y in by choosing a number in the y column.

1=_x+3

1=(2)(-1)+3

1=1

Part 2.

do the same

5=3(2)

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5=5

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3 years ago

Ramal filled 3 pages in a stamp album.This is one sixth of the pages in the album.How many pages are their in ramals stamp album

padilas [110]

Well

x/6=3/*6
x=18

There are 18 pages in Ramals stamp album

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3 years ago

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If ∡P and ∡Q are complementary angles (90°), m∡P = 7x + 3, and m∡Q = 16x – 5, find m∡P.

bezimeni [28]

Answer:

Step-by-step explanation:

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3 years ago

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2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email protected]</a> - <a href

Phantasy [73]

Answer:

Step-by-step explanation:

$2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3}) } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}$

$\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)$

$or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )$

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3 years ago