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Solve. Check that your answer is reasonable. Paula's painting has a perimeter of 1.22 meters. She wants to put ribbon around the

iren2701 [21]

Answer:

5 pieces

Step-by-step explanation:

Given:

Paula's painting has a perimeter of 1.22 meters.

She wants to put ribbon around the edge.

If the ribbon comes in pieces that are 25 centimeters long.

Question asked:

How many pieces of ribbon does she need to go all the way around her painting?

Solution:

Perimeter of painting = 1.22 meters

First of all we will convert it into centimeters:-

As we know:

1 meter = 100 centimeters

1.22 meters = 100 $\times$ 1.22 = 122 centimeters

Now, as given that ribbon comes in pieces of 25 cm long and total we should have 122 cm to go all the way around the painting.

Number of pieces of ribbon will be needed = $\frac{122}{25} =4.88\$

Thus, she need 5 pieces of 25 cm long ribbon to go all the way around the painting.

<u>Note</u>:-This is by default understood that few length of 5th ribbon will be left over.

3 0

3 years ago

Which expression is equivalent to 27 ( − 2 3 x + 1 3 ) − 5 x ?

klemol [59]

Answer:

KINGSHIP NO NIJINSKY

Whenever I'm alone with you

You make me feel like I am home again

Whenever I'm alone with you

You make me feel like I am whole again

Whenever I'm alone with you

You make me feel like I am young again

Whenever I'm alone with you

You make me feel like I am fun again

However far away

I will always love you

However long I stay

I will always love you

Whenever I'm alone with you

You make me feel like I am free again

Whenever I'm alone with you

You make me feel like I am clean again

However far away

I will always love you

However long I stay

I will always love you

Whatever words I say

I will always love you

However far away

I will always love you

However long I stay

I will always love you

whatever words I say

I will always love you

I'll always love you

I love you

-Adele

Step-by-step explanation:

7 0

3 years ago

Car dealerships claim to make most of their money from servicing cars. In a certain month, an Acura dealership sold fifteen less

MA_775_DIABLO [31]

Answer:

New cars sold = 20,

Used cars sold = 25

Cars serviced = 290

Step-by-step explanation:

In a month they sold fifteen less used cars than twice the number of new cars.

Lets say 'x' number of new cars were sold, then:

The number of used car sold is:

$2\times x-15=2x-15$

In the same month they serviced fifty more than twelve times the number of new cars sold. So the number of cars serviced is:

$12\times x+50=12x+50$

Altogether they sold or serviced 335 cars, so the sum of all the cars sold and serviced should be 335:

$x+(2x-15)+(12x+15)=335$

Solving for 'x' we get:

$x+2x+12x-15+50=335$

$15x+35=335$

$15x=335-35=300$

$x=\frac{300}{15}=20$

Therefore, the number of new cars sold in that month is 20.

Number of used car sold $=2x-15=2\times 20-15=40-15=25$

Number of cars serviced $=12\times x+50=12\times20+50=240+50=290$

We can also cross check by summing them up:

$290+25+20=335$

8 0

3 years ago

→

Juli2301 [7.4K]

Answer 5.1
Order them from least to greatest and find the middle number. Or by calculating the mean by adding together the middle values and dividing them by two.

3 0

2 years ago

How many prime numbers are between 45 and 72

Dmitry [639]

There are 7 prime numbers: 47,51,53,59,61,67,and71

Hope that helped:)

6 0

3 years ago

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