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4 years ago

Can someone please help :(

Mathematics

2 answers:

denpristay [2]4 years ago

6 0

The domain is the set of all real numbers and the domain is the set of all real numbers

GuDViN [60]4 years ago

3 0

Answer:The domain is the set of all numbers, and the range is the set of all real numbers.

Step-by-step explanation:

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To covert 180 seconds to minutes, which proportion should you use?

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At store A, apples are $3.99 for 5 apples. At store B, apples are $20 for 10 apples. Which is the better deal?

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Type SSS, SAS, ASA, SAA, or HL to<br> describe these triangles.

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3 years ago

Find the absolute value:<br> 5.34 -4 2/11 0<br> -6 3/5 -2.12 8.2

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I hope this helps u! :D

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3 years ago

write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through

madam [21]

The exponential equation is $y = \frac23(3)^{-x+0.74} + 2$

<h3>How to determine the equation?</h3>

An exponential function is represented as:

$y = b^x$

The base is 3.

So, we have:

$y = 3^x$

It is stretched vertically by 2/3.

So, we have:

$y = \frac23(3)^x$

When reflected over the y-axis, we have:

$y = \frac23(3)^{-x}$

An asymptote of y = 2, makes the function becomes

$y = \frac23(3)^{-x} + 2$

Lastly, it passes through the point (0, 3.5).

So, we have:

$y = \frac23(3)^{-x+h} + 2$

This gives

$3.5 = \frac23(3)^{-0+h} + 2$

$3.5 = \frac23(3)^{h} + 2$

Subtract 2 from both sides

$1.5 = \frac23(3)^{h}$

Multiply by 3/2

$2.25 = (3)^{h}$

Take the logarithm of both sides

log(2.25) = h * log(3)

Solve for h

h = 0.74

Substitute h = 0.74 in $y = \frac23(3)^{-x+h} + 2$

$y = \frac23(3)^{-x+0.74} + 2$

Hence, the exponential equation is $y = \frac23(3)^{-x+0.74} + 2$

Read more about exponential equation at

brainly.com/question/23729449

#SPJ1

3 0

2 years ago