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Verdich [7]
3 years ago
9

Find thetwo consecutive integers whose product is 24​

Mathematics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

There is no solution to this equation that is an integer for x.

Step-by-step explanation:

x is the first integer, and x+1 the second

x(x+1) = 24\\x^{2} + x - 24 =0\\

x = \frac{-1+\sqrt{1^{2}+4*24}}{2} =\frac{-1+\sqrt{97}}{2}\\x = \frac{-1-\sqrt{1^{2}+4*24}}{2} =\frac{-1-\sqrt{97}}{2}

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Answer:

sure

Step-by-step explanation:

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3) add a zero under the 3 to hold the ones place and multiply 6 by 1 then 4 then 6 and since we’re working with the tenths place now and dont forget to carry numbers if you need to

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4) add your two numbers together

    1 1    

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+___1923_

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so that is your answer “40383”

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