If measure of angle X = 63, what is measure of angle YZW? A. 63 B. 90 C. 17 D. 27

Solve the compound inequality. 3x + 1 <4 or 9x > 31

WINSTONCH [101]

Answer:

Step-by-step explanation:

3x < 4 - 1 or x > 31/9

3x < 3 or x > 31/9

x < 1 or x > 31/9

7 0

3 years ago

Anyone know the answer?

yan [13]

Answer:

0.

Step-by-step explanation:

The angle whose sine is 5/12 = 22.62 degrees and in Quadrant II it is

180 - 22.62 degrees

The angle whose tan is (5/12) = 22.62.

So we can write α as 180 - α and β as α.

sin (α+β) = sin ( 180 - α = α) = sin 180

= 0.

7 0

3 years ago

Solve the smetaneous equatan graphically x-2y=1 2x-y=2 given the range of x from-3 to 3 choose a suitable scale

DedPeter [7]

Answer:

(2, 0)

Step-by-step explanation:

Given system:

x - 2y = 1
2x - y = 2

In order to solve it graphically, graph both lines and find the point of their intersection.

Graphing easy if you plot the x- and y- intercepts and connect them with a line.

See attached.

Both lines have same x-intercept, which is also the solution: (2, 0)

8 0

3 years ago

Read 2 more answers

Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.

Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

$\displaystyle T_ n = ar^{n-1}$

Where Tₙ is the nth term, a is the initial term, and r is the common ratio.

We are given that the fifth term T₅ = 96 and the eighth term T₈ = 768. In other words:

$\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}$

Substitute and simplify:

$\displaystyle 96 = ar^4 \text{ and } 768 = ar^7$

We can rewrite the second equation as:

$\displaystyle 768 = (ar^4) \cdot r^3$

Substitute:

$\displaystyle 768 = (96) r^3$

Hence:

$\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2$

So, the common ratio r is two.

Using the first equation, we can solve for the initial term:

$\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}$

In conclusion, of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

7 0

3 years ago

Need help badly #15 Find the area of each sector.

Ber [7]

The highlighted sector is exactly 3/4 of the circle area, because $\frac{3\pi}{2}$ is 3/4 of $2\pi$ which is a complete rotation.

Since you are given the radius, you can compute the area as

$A = \pi r^2 = 16\pi$

So, 3/4 of this area would be $12\pi$ squared cm.

The remaining sector, of course, is $4\pi$ squared cm.

6 0

3 years ago