Range: (-infinity, 4]
the ] signifies that the four is included in the range, rather than ) which means reaching but never approaching. this is why we use ( ) for - and + infinity, cause it can never be reached.
minimum: (-infinity, infinity)
keep it in same format as you have for the maximum
increasing
the interval -infinity
Answer:
A) Suppose we have an onedimensional situation.
in the 0 of our x-axis, we have a fruit tree, and we want to rest at a distance no bigger than 6 ft of the tree, then all the possible positions of our resting place are:
x ∈(-6ft, 6ft)
we can write this as: IxI < 6ft
b) now we think the opposite situation, we want to rest at least 6ft away from the tree, then we have that:
x ∉ [-6ft, 6ft].
or IxI > 6ft.
So you can see that the difference in those two cases is if we want to be "inside a given range" (for the first case) or "outside a given range" (for the second case).
Answer:
B: 1 × 10^5
Step-by-step explanation:
B is correct and C is not becasue you have to have the number multiplied by 10 to a power because then you wouldn't know what number to use as the base. I hope this helps. :)
The range is the output or the y values in the case of this function. The only y value on this function is 1 therefore the range is 1
:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
