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Elodia [21]
3 years ago
6

How many 1/2 foot pieces can be cut from 6 foot ribbon?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0
Number of ribbons that can be cut = 6 ÷ 1/2 
Number of ribbons that can be cut = 6 x 2/1
Number of ribbons that can be cut = 12 

 -----------------------------------------------------------------------------------------
Answer: 12  1/2 foot pieces can be cut from 6 feet ribbon
 -----------------------------------------------------------------------------------------

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The height of a triangle is 8ft greater than the base. The area of the triangle is 136.5 square ft. Find the length of the base
mixer [17]

Answer:

the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

Step-by-step explanation:

Note that the formula for the area of a triangle is A = (1/2)(base)(height).  Let's abbreviate that to A = (1/2)(b)(h).   We are told that h = b + 8.

Then A = 136.5 = (1/2)(b)(b + 8), or

               (after multiplying both sides by 2)

          A = 273 = b^2 + 8b

                which, when put into standard quadratic form, becomes:

b^2 + 8b - 273 = 0

The coefficients of this quadratic are a = 1, b = 8 and c = -273.

Thus, the discriminant is b^2 - 4ac, or 64 - 4(1)(-273) = 1156 = 17^2.

The roots are then

      -8 ± √1156            -8 ± 17

x = --------------------  =  ------------ = 9/2 and -25/2

              2                          2

Only the root 9/2 makes sense here, because measurements of length are positive.

Thus, the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

3 0
3 years ago
Please someone help with my math
Pepsi [2]

Answer:

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Step-by-step explanation:

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geniusboy [140]
Your answer is 6 centimeters because you would have to subtract 3 from 9. Hence, your answer is 6. 

Hope I helped!
4 0
3 years ago
Read 2 more answers
list the pair of congruent angles and the extended proportion that relations the corresponding sides for the similar polygons KL
kherson [118]

Answer:  

In Polygons KLMNP and HGFDC,

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And, Sides KL, LM, MN, NP and PK are corresponding to sides HG, GF, FD, DC and CH

If the two figures are similar then their corresponding sides and angles are congruent.

Therefore, If  Polygon KLMNP is similar to HGFDC,

Then, ∠ K ≅ ∠ H,  ∠ L ≅ ∠ G,  ∠ M ≅ ∠ F,  ∠ N ≅ ∠ D,   ∠ P ≅ ∠ C

And, KL ≅ HG,  LM ≅ GF,  MN≅FD,  NP≅DC,  PK≅CH

7 0
3 years ago
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Oksanka [162]

A function is said to even if it returns the same output when given two opposite inputs:

f(x) = f(-x)

In your case, you have

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And since \cos(x) = \cos(-x), the proof is concluded.

8 0
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