<h2><u>Problem Solving</u>:-</h2>
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.
<h2><u>Solution</u>:-</h2>
Since the distance d varies directly as the time t, then d = kt.
Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.
<h2><u>Answer</u>:-</h2>
- Therefore, the constant of variation is 10.
Answer:
0.1469
Step-by-step explanation:
Given from the question;
Mean=8.4 hrs=μ
Standard deviation=1.8 hrs=δ
Sample size, n=40
Let x=8.7
z=(x-μ)÷(δ÷√n)
Find z(8.7)
z=(8.7-8.4)÷(1.8÷√40)
z={0.3×√40}÷1.8=1.05409
z=1.0541
Read from the standard normal probabilities table
P(z>1.0541)
=0.1459
Answer:
Area of the sector = 47.52π
Step-by-step explanation:
Area of the sector of the circle;
A = ∅ / 360 * πr²
We know that;
∅ = 120
r = 12
So now we can substitute;
A = (120 / 360) * π(12)²
A = 0.33 * 144π
A = 47.52π
Hope this helps!
Answer:
70
Step-by-step explanation:
Since these two are same side interior angles, their measures must be supplementary. This means that they must add up to 180 degrees. Therefore:
45+2x-5=180
2x+40=180
2x=140
x=70
Hope this helps!
