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lakkis [162]
3 years ago
8

100 points! Mhanifa please help. Look at the picture attached. I will mark brainliest!

Mathematics
2 answers:
patriot [66]3 years ago
6 0

Answer:

Step-by-step explanation:

BD is the perpendicular disector of isosceles triangle DAC

AB=BC

6x=9x-27

3x=27

x=9

BC=9x-27=54

For triangle JKL and JML,

KL=ML

JL=JL

JK=JM from properties of right-angled triangle

So triangle JKL and JML are congruent

<KJL = <MJL

4x+6=3x+10

x=4

<KJL=4*4+6=22

natima [27]3 years ago
5 0

Answer: BC = 54  <kjm=44

Step-by-step explanation:

1st 0ne-

if you look at it as 2 triangles with D being the shared side- I can determine that the angles are congruent (by SSA theorem)

so

6x=9x-27  (by corresponding parts of congruent Theorem)

-3x=-27

x=9

BC- 9(9)-27= 81-27=54

2nd one-

J bisects KJM

4x+6=3x+10

x=4

3(4)+10= 22

4(4)+6= 22

KJM= 22+22= 44

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Answer:

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Probability= Number of outcomes/ total number of outcomes

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Write the following ratio using two other notations. 8:9
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8/9 8 to 9

Step-by-step explanation:

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Kayden brought 9 packs of paper for $27 how much will you pay for 11 packs of paper​
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4 years ago
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Answer:

5 gallons per week

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3 0
3 years ago
The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning ca
Fed [463]

Answer:

Sam had a finish time with a z-score of -2.93.

Karen had a finish time with a z-score -1.91.

Sam had the more convincing victory.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sam:

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.

So \mu = 186.94, \mu = 0.372, X = 185.85

Z = \frac{X - \mu}{\sigma}

Z = \frac{185.85 - 186.94}{0.372}

Z = -2.93

Sam finishing time was 2.93 standard deviations below the mean.

Sam had a finish time with a z-score of -2.93.

Karen:

The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

So \mu = 110.7, \sigma = 0.115, X = 110.48

Z = \frac{X - \mu}{\sigma}

Z = \frac{110.48 - 110.7}{0.115}

Z = -1.91

Karen finishing time was 1.91 standard deviations below the mean.

Karen had a finish time with a z-score -1.91.

Who had the more convincing victory?

Sam finishing time was 2.93 standard deviations below the mean.

Karen finishing time was 1.91 standard deviations below the mean.

Sam finished more standard deviations below the mean than Karen, that is, he was faster relative to his competition than Karen.

So Sam had the more convincing victory.

8 0
3 years ago
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