3 years ago

What is the average rate of change of the function below on the interval [0, 0.5]?

2 answers:

8 0

Answer:

Step-by-step explanation:

F(0)= 0^2+7(0)+10/ 0^2 - 7(0)+6 = 1.67

F(0.5)= 0.5^2+7(0.5)+10/ 0.5^2 - 7(0.5)+6 = 5

$RateofChange = \frac{F(0.5) - F(0)}{0.5 - 0} = 6.667$

7 0

Answer:

add all the numbers and divide by 4

Step-by-step explanation:

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