Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
The answer is straightforward, by the "rule of product":
There are
3×8×2=48
3×8×2=48
different combinations (distinct possible cars) that can be created.
There 33 choices for body style; 88 choices for exterior colors, and 22 choices of interior color schemes:
Since each of these choices are independent (the choice of body style doesn't depend on exterior or interior color, e.g.) we multiply the number of choices for each quality to obtain: 3×8×2=483×8×2=48 distinct ways to create a car
Answer:
a. The constant = 45
b. The unit rate is 45 miles per hour
c. d = 45t
Step-by-step explanation:
a. ∵ d ∝ t
∴ d = kt
∵ d = 90 at t = 2
∴ 90 = k(2)
∴ k = 90 ÷ 2 = 45
∴ The constant of proportionality is 45
b. ∵ k = d(miles) ÷ t(hours) = 45
∴ The unit rate is 45 miles per hour
c. The equation is ⇒ d = 45t
Subtract 6 which leaves u with -3p=-18 then divide by three on both sides to get p=6
11/3, 1.3, 1.34 Is the correct way to put it. PLZ give me the Brainliest answer. :)
