What is the area of a triangle with vertices at (−4, 1) , (−7, 5) , and (0, 1) ?

1 answer:

3 0

Plot the points on a graph. Connect the dots into a triangle. See that the height of the triangle is from y=5 down to y=1. So the height is 4 units.
Area of a triangle: A = (1/2)BH

You need to find the length of the base. Which is from point (-4,1) to (0,1). You can use the distance formula r just see from the graph that the base is 4 units.

A = (1/2)(4)(4)
A = 8

** Distance formula fyi
d² = (X-x)² + (Y-y)²
with points (X,Y) and (x,y)
<span>
</span>

You might be interested in

What is the slope of a line that is perpendicular to the line represented by the equation y=3/4x-1/2?

kherson [118]

The answer is: " - (4/3) " .
____________________________________
Explanation:
____________________________________
The original equation given has a slope of (3/4).

Note: We know this since the equation for the slope of the line is written in "slope-intercept form" ; also known as: "point-slope form"; that is:

" y = mx + b " ; in which "m" (the coefficient of "x") is the slope.
____________________________________________________
The slope of a line PERPENDICULAR to an equation, when written in "slope-intercept form", is the "negative reciprocal" of the slope of the original line.

Hence, the negative reciprocal of "(3/4)" is: "-(4/3)" .
____________________________________________________

5 0

3 years ago

Which one is equivalent <br><br> Look at the pic

Paha777 [63]

(3/5)³

=(3³)/(5³)

=27/125

---------------

As:

3*3*3=27

And:

5*5*5=125

6 0

3 years ago

Read 2 more answers

Make sure to round the whole number

Elis [28]

Use calcutlator and it all smushed up i can barley see it

5 0