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3 years ago

11

A field hockey field is rectangular. Its width is 54.88 meters, and its perimeter is 289.76 meters. Find the length of the field

.

2 answers:

Alchen [17]3 years ago

6 0

Answer:

90 PLEASE MARK ME BRAINLLIEST

Step-by-step explanation:

289.76-54.88-54.88=180/2=90

Alchen [17]3 years ago

5 0

Answer:

2eoixn[

Step-by-step explanation:

x cpi3urqbeqfpb n

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Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

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✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

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Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago

The sum of the two shorter sides of a triangle must be equal to the longest side to be classified as a triangle

kogti [31]

Answer:

False

Step-by-step explanation:

For example if you follow the pythagoras theorem a triangle has sides of 3,4 and 5

but when you add 3 and 4 they do not give you 5

so that is false

5 0

3 years ago