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daser333 [38]
3 years ago
14

Subtract the second equation from the first. A)12x=22 B) 4x=6 C) 6y=22 D) -6y=6

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

B) 4x = 6

Step-by-step explanation:

VLD [36.1K]3 years ago
4 0

Answer:

Its B

Step-by-step explanation:

I had the same question today what a coincidence! :)

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Timed test please answer ASAP
emmasim [6.3K]

Answer:B

Step-by-step explanation:

4 0
2 years ago
A ball is thrown from an initial height of 3 feet with an initial upward velocity of 28 ft/s. The ball's height h (in feet) afte
dimaraw [331]

The value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

Given that the height of the ball at time t is given by the function,

h(t) = 3+ 28t -16t^2

where t is in seconds and h is in feet.

Now, the height of the ball is given to be 11 feet, therefore, substituting the value of h in the function as 11,

h(t) = 3+ 28t -16t^2\\\\11 = 3+ 28t -16t^2\\\\-16t^2 + 28t +3 -11 = 0\\\\-16t^2 + 28t -8 = 0

Now, solving the given quadratic equation, we will get,

x= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-(28)\pm \sqrt{(28)^2-4(-16)(-8)}}{2(-16)}\\\\t= 0.36\ or\ 1.39

Hence, the value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

Learn more about Quadratic Equations:

brainly.com/question/2263981

#SPJ1

7 0
2 years ago
Which is a solution to the equation |10-5y|=20<br><br>y=2<br><br>y=4<br><br>y=6<br><br>y=10
Pavlova-9 [17]

Answer:

y=6

Step-by-step explanation:

|10-5y|=20

Since the absolute value is isolated, we can then separate the equations

For absolute values, there is a positive and negative when we remove the absolute values.

10-5y = 20          10-5y= -20

Subtract 10 from each side

10-10-5y = 20-10          10-10-5y= -20-10

-5y = 10                             -5y = -30

Divide by -5

-5y/-5 =10/-5                    -5y = -30/-5

y =-2                                      y =6

7 0
3 years ago
Sam and Jon are attending the same summer camp. The camp is 293 miles away from each of their homes. The graph shows Jon's const
dsp73
Total time taken by Jon was 4.5 hours
Time taken by Sam was 5.5 hours
This implies that John traveled faster than Sam because he took shorter time to get to the camp, thus we conclude that from the given information, the correct answer is:
Sam and Jon traveled at the same rate of speed to camp.
3 0
3 years ago
Six percent (6%) of all shoppers make an impulse purchase at the check-out counter in a grocery store. If a store has 650 custom
Nookie1986 [14]

Answer:

(e) 39

Step-by-step explanation:

The expected value (or the average number) of impulse purchases per day is given by the probability of an impulse purchase being made (6%) multiplied by the daily number of customers (650):

E(X) =P(X)* n\\E(X) = 0.06*650\\E(X) = 39

The average number of impulse purchases is 39 per day.

3 0
3 years ago
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