Answer:
C(50;-20)
Step-by-step explanation:
The question is asking for the midpoint of the line.
The triangle is formed by placing a line directly from the y-axis to the x-axis.
The midpoint theorem is[ (x1+x2)/2 ; (y1+y2)/2 ].
your coordinates at A is (0;-40), because the x value is 0 on the line as shown in the diagram above point A.
Your coordinates for B are (100;0)
C[(x1+x2)/2 ; (y1+y2)/2 ]
C [(0+100)/2 ; (-40+0)/2 ]
C[ 100/2 ; -40/2]
C (50 ; -20)
We have trapezoid with congruent legs.
30x + 11y = 2x + 3
28x +11y = 3
Also we have
30x + 11y = 12
We got 2 equations:
30x + 11y = 12
28x +11y = 3 (*-1) -----> -28x -11y = -3
30x + 11y = 12
<u> -28x -11y = -3</u>
2x = 9
x=9/2
30x + 11y = 12 ------> 30*9/2 +11y =12 ------> 135+11y =12, ---> 11y = - 123,
y= - 123/11
Answer:
No solution
Step-by-step explanation:
Associative property Says that you can add or multiply regardless of how the numbers are group
