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Eva8 [605]
3 years ago
5

A candy machine contains 100 gumballs: 23 grape, 26 blueberry, 16 cherry, and 35 strawberry. What is the experimental probabilit

y of choosing a blueberry gumball as a percent and a fraction?
Mathematics
1 answer:
balu736 [363]3 years ago
4 0
The answer is 13/50th or 26%
 You simply take the amount of blueberries and divide it by the total number of gumballs and you get 13/50 or 26%
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Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c
Allushta [10]

Let the cost of one cup of hot chocolate  be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = 3x+4y=25.50   ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

y=\frac{2x}{3}   .... (2)

Putting the value of y from (2) in (1)

3x+4(\frac{2x}{3})=25.50

=3x+\frac{8x}{3}=25.50

=\frac{9x+8x}{3}=25.50

=17x=76.5

x=4.5

y=\frac{2x}{3}

=\frac{2*4.5}{3}

y =3

Hence each cup of hot chocolate is $4.50

Each cup of tea is $3.

7 0
3 years ago
A jar of marbles contains 7 blue marbles, 12 yellow marbles, 8 green marbles, and 5 red marbles. Use this information to answer
AnnZ [28]
Total marbles = 7 + 12 + 8 + 5 = 32
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Yellow marbles = 12

P(green ,then yellow) = (8/32)(12/32) = 3/32

Answer: The probability is 3/32
8 0
3 years ago
Find the coordinates of the midpoint M of ST???????. Then find the distance between points S and T. Round the distance to the ne
Law Incorporation [45]
(7, 5)
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3 0
3 years ago
Read 2 more answers
Which of the following values are solutions to the inequality 1+5x&lt;4?<br> I.6 <br> II.5<br> III.2
Paraphin [41]

Answer:

x < .6

Step-by-step explanation:

1+5x<4

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1-1+5x<4-1

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Divide each side by 5

5x/5 <3/5

x < .6

4 0
3 years ago
Evaluate: 11 + sqrt(-4 + 6×4÷3)
Murrr4er [49]

Answer:

11+\frac{2\sqrt{15}}{3}

Step-by-step explanation:

11 + \sqrt{(-4 + 6\times4\div3)} \\\\11+\sqrt{\frac{-4+6\times \:4}{3}}\\\\\sqrt{\frac{-4+6\times \:4}{3}}=\frac{2\sqrt{5}}{\sqrt{3}}\\\\=11+\frac{2\sqrt{5}}{\sqrt{3}}\\\\\frac{2\sqrt{5}}{\sqrt{3}}=\frac{2\sqrt{15}}{3}\\\\=11+\frac{2\sqrt{15}}{3}

3 0
3 years ago
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