The solution to given expression
is
or 3.8571
<em><u>Solution:</u></em>
Given expression is:

<em><u>First let us convert the mixed fraction to improper fraction</u></em>
Multiply the whole number by the denominator.
Add the answer from Step 1 to the numerator.
Write answer from Step 2 over the denominator.
Thus we get,

Now the given expression becomes,

Convert the problem to multiplication by changing the division sign to multiplication and inverting the fraction to the right of the sign

Multiply the numerators, multiply the denominators, and leave the product in factored form

In decimal form we get,

Thus the solution to given expression is
or 3.8571
what question are you wanting to be answered?
The answer is since the the angle on the inside of the triangle is 90 degrees by supplementary angles and the other angle that is not p is 47 degree, also by supplementary angles. Thus you take 90+47=137 and subtract it from 180 since that is is the total angle sum of a triangle and you get 43 degrees or answer b
Answer:
$48.87
Step-by-step explanation:
Let the deposited amount between the March 15th and the March 20th be x
Balance on 15th march = $56.75
The bank returned all the cancelled checks but too. One check was for $5 and the other was for $13.25
And he also deposited x amount
After deposits and deductions
So, balance = 56.75 +x - (13.25+5)
The new balance on 20th march = $87.37
⇒
⇒
⇒
⇒
⇒
Hence Carlos deposited $48.87 in his account between the March 15th and the March 20th.
Answer:
Step-by-step explanation:
The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function
g(x,y) = sin(π(x−5y)
∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))
(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]
(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]
∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j
∇g = π [cos (π(x−5y))] [î - 5j]
So, the question requires a direction vector and a point to fully evaluate this directional derivative now.