At Thanksgiving, Mrs. Jones overcooked the turkey so all but StartFraction 4 Over 5 EndFraction of it had to be thrown away. The
2 answers:
You might be interested in
First we find the vertex of parabola 
The vertex of parabola is
Here,
b = coefficient of x term
a = coefficient of x² term
For given parabola, b = 0 , a = -12
So,
And,
Thus the vertex of parabola is (0, 7)
To find another point on parabola, substitute x by 1.
So the second point on parabola is (1,-5)
The plot of parabola is shown in image below:
The vertex of parabola is
Here,
b = coefficient of x term
a = coefficient of x² term
For given parabola, b = 0 , a = -12
So,
And,
Thus the vertex of parabola is (0, 7)
To find another point on parabola, substitute x by 1.
So the second point on parabola is (1,-5)
The plot of parabola is shown in image below:
M∠A′B′C′ = m∠ABC would be the answer for this. if you could give me a pic, I could answer. I don't see Triangle ABC
