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algol [13]
2 years ago
5

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

will be needed to produce 725 mL of a solution that has a concentration of Na ions of 1.50 M
Chemistry
1 answer:
ddd [48]2 years ago
5 0

Answer:

178.35g

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles ÷ volume

Based on the information provided in this question, molarity (M) of the solution = 1.50 M, volume = 725 mL = 725/1000 = 0.725L, n = ?

1.50 = n / 0.725

n = 1.50 × 0.725

n = 1.0875mol

Molar mass of Na3PO4

23(3) + 31 + 16(4)

= 69 + 31 + 64

= 164g/mol

Mole = mass ÷ molar mass

1.0875 = mass/164

mass = 178.35g

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