All categories

4 years ago

How many moles in 1.00g of salicylic acid?

Chemistry

1 answer:

salantis [7]4 years ago

7 0

Answer:- 0.00724 moles.

Solution:- Grams of salicylic acid are given and it asks to calculate the moles.

For the moles, we divide the grams by the molar mass.

Formula of salicylic acid is $C_7H_6O_3$

Molar mass = 7(12.01)+6(1.01)+3(16.00)

= 84.07+6.06+48.00

= 138.13 gram per mol

We could make the dimensional analysis set up for showing unit cancellation and have the moles.

$1.00g(\frac{1mol}{138.13g})$

= 0.00724 moles

So, there will be 0.00724 moles of salicylic acid in it's 1.00 gram.

You might be interested in

Please help thank you (15 points)

Eva8 [605]

Answer:

D. The sun has less gravitational pull on Pluto because it is farther away.

6 0

3 years ago

The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t

Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)$

The expression of $K_p$ for above reaction follows:

$K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}$

We are given:

$K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm$

Putting values in above equation, we get:

$0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm$

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0

3 years ago

The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.

Brrunno [24]

Answer:

The molecular formula of the compound is $C_{8}H_{16}O_{4}$ . The molecular formula is obtained by the following expression shown below

$\textrm{Molecular formula }= n\times \textrm{Empirical formula}$

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is $C_{2}H_{4}O$

Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.

Empirical formula mass of the compound = $\left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}$

$n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4$

$\textrm{Molecular formula }= n\times \textrm{Empirical formula}$

Molecular formula = 4 $\times$ $C_{2}H_{4}O$

Molecular formula is $C_{8}H_{16}O_{4}$

6 0

3 years ago

How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and

il63 [147K]

Answer:

How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and a density of water is 2gcm -3

R.d= relative density of substance/ relative density of water

R.d= 2/2

R.d= 1gcm-3

Explanation:

5 0

3 years ago

Which does your digestive system use to break down food molecules? Bases or Acids

Harman [31]

Answer:

acid

Explanation:

4 0

3 years ago