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olga55 [171]
3 years ago
7

How many moles in 1.00g of salicylic acid?

Chemistry
1 answer:
salantis [7]3 years ago
7 0

Answer:-  0.00724 moles.

Solution:- Grams of salicylic acid are given and it asks to calculate the moles.

For the moles, we divide the grams by the molar mass.

Formula of salicylic acid is C_7H_6O_3

Molar mass = 7(12.01)+6(1.01)+3(16.00)

= 84.07+6.06+48.00

= 138.13 gram per mol

We could make the dimensional analysis set up for showing unit cancellation and have the moles.

1.00g(\frac{1mol}{138.13g})

= 0.00724 moles

So, there will be 0.00724 moles of salicylic acid in it's 1.00 gram.

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What is the mass sample of 0.0500 moles of zinc chloride ?
vlabodo [156]

Answer:

6.82g

0.59moles

Explanation:

1. What is the mass sample of 0.0500 moles of zinc chloride ?

Given parameters:

Number of moles ZnCl₂ = 0.05moles

Unknown:

Mass of the sample  =  ?

Solution:

To find the mass of a substance using the number of moles, it would be pertinent to understand what mole is.

A mole is a substance that contains the avogadro's number of particles.

It relates to the mass using the expression below;

                Mass of a substance  = number of moles x molar mass

Molar mass of  ZnCl₂;

        Atomic mass of Zn  = 65.4g/mol

                                   Cl = 35.5g/mol

Molar mass = 65.4 + 2(35.5)  = 136.4g/mole

Mass of a substance  = 0.05 x 136.4  = 6.82g

2. How many moles of potassium sulfide are in a 65.50g sample?

Given parameters:

Mass of K₂S  = 65.5g

Unknown:

Number of moles  = ?

Solution:

The number of moles of any substance is related to mass using the expression below;

              Number of moles  = \frac{mass}{molar mass}

Molar mass of K₂S  = 2(39) + 32  = 110g/mol

              Number of moles  = \frac{65.5}{110}   = 0.59moles

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a flas
valentina_108 [34]

Answer:

Kp = 0.022

Explanation:

<em>Full question: ...With 2.3 atm of ammonia gas at 32. °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of hydrogen gas to be 0.69 atm. </em>

<em />

The equilibrium of ammonia occurs as follows:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where Kp is defined as:

Kp = \frac{P_{N_2}P_{H_2}^3}{P_{NH_3}^2}

<em>Where P represents partial pressure of each gas.</em>

<em />

As initial pressure of ammonia is 2.3atm, its equilibrium concentration will be:

P(NH₃) = 2.3atm - 2X

<em>Where X represents reaction coordinate</em>

<em />

Thus, pressure of hydrogen and nitrogen is:

P(N₂) = X

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As partial pressure of hydrogen is 0.69atm:

3X = 0.69

X = 0.23atm:

P(NH₃) = 2.3atm - 2(0.23atm) = 1.84atm

P(N₂) = 0.23atm

P(H₂) = 0.69atm

Kp = \frac{0.23atm*0.69atm^3}{1.84atm^2}

<h3>Kp = 0.022</h3>
8 0
3 years ago
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