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sleet_krkn [62]
3 years ago
11

Six friends ate in a restaurant together and split the total cost, c, equally. Each person paid less than $8. Which statements r

epresent the scenario? Check all that apply.
The total cost of the food, c, can be represented by the inequality StartFraction c Over 6 EndFraction less-than 8.

The total cost of the food could be $48
.
The total cost of the food could be $36.

When graphed, the number line would be shaded to the left of the maximum value.

The total cost of the food must be greater than $60.

100 BRAINLY POINTS
Mathematics
2 answers:
dolphi86 [110]3 years ago
4 0

Answer:

A, C, and D are the correct answers.

Step-by-step explanation:

A) The total cost of the food, c, can be represented by the inequality c/6 < 8

C) The total cost of the food could be $36.

D) When graphed, the number line would be shaded to the left of the maximum value.

It's A because the 6 friends SPLIT the total cost which is c, and each person paid LESS than $8 dollars, not $8 and above. So it will look like, "total cost/6 people is less than 8" aka "c/6 < 8"

It's C because if each person paid less than $8 dollars, the total is anything under 48. (6 x 8 = 48, and 6 x 6 = 36, and 6 is less than 8.)

It's D because anything LESS than the max value could be the value to c/6. So anything to the left of 8, is less than 8, and anything to the right of 8, is greater than 8, and we want what is "< 8" less than 8 so it has to be to the left.

Natali [406]3 years ago
3 0

Answer:

The total cost could be $36

Step-by-step explanation:

36/6 = 6

6 is less than 8

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Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

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(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

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