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vichka [17]
3 years ago
6

Which similarly proves the two triangles are similar?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

If their angles are the same, if they are proportional, if it states so

Step-by-step explanation:

I don't see the image you sent, but just naming different things that proves how triangles are similar.

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Find the surface area of the cylinder and round to the nearest tenth. (It is recommended that you use the π button on your calcu
elena-s [515]

The surface area of the cylinder is 18.84 square feet

<h3>How to determine the surface area?</h3>

The given parameters are

Height, h = 2 ft

Diameter, d = 2 ft

The radius (r) is half of the diameter (d)

This is calculated as:

Radius = Diameter/2

So, we have:

r = d/2

Substitute 2 for d

r = 2/2

Evaluate the quotient i.e. divide 2 by 1

r = 1

The surface area is then calculated using the following formula

A = 2πr² + 2πrh

Substitute the given values in the above equation

So, we have:

A = 2 * 3.14 * 1^2 + 2 * 3.14 * 1 * 2

Evaluate the exponents

A = 2 * 3.14 * 1 + 2 * 3.14 * 1 * 2

Evaluate the products

A = 6.28 + 12.56

Evaluate the sum

A = 18.84

Hence, the surface area of the cylinder with the given height and radius is 18.84 square feet

Read more about surface area at:

brainly.com/question/2835293

#SPJ1

4 0
2 years ago
The model represent an equation <br> What is the value of x?
EastWind [94]

Answer:

X equals 3

Step-by-step explanation:

if 3 circles are already shown and there are 9 circles total. x = 3

3 0
2 years ago
Iris weighed 5 large watermelons from her garden. Here are the weights in pounds. 17,11,21,24,22 what is the mean weight
Rufina [12.5K]

Answer:

Mean weight = 19 pounds

Step-by-step explanation:

From the question given above, the following data were obtained:

17, 11, 21, 24, 22

Number of data (n) = 5

Mean weight =?

The mean of a set of data is the value obtained by adding all the data together and dividing the result obtained by the total number of data. Thus, the mean can be obtained as follow:

Summation of data = 17+ 11 + 21 + 24 + 22

= 95

Number of data = 5

Mean = Summation of data / Number of data

Mean = 95 / 5

Mean weight = 19 pounds

Therefore, the mean weight of the data is 19 pounds

5 0
3 years ago
PLZ HELP ME I NEED THIS FAST WILL GIVE BRAINLIEST
Bas_tet [7]

Step-by-step explanation:

The formula the amusement parc use is  100y-39000=55(x-800)

The slope intercept form of a function is wriiten generally as:

y = mx+c

  • m is a slope
  • c is a constant and represents the y-intercept
  • x is a variable
  • y is the input of the function

Let's rewrite our equation in the precedent form

  • 100y-39000 = 55(x-800)
  • 100y -39000 = 55x-44000    add 39000 in both sides
  • 100y-39000+39000 = 55x-44000+39000
  • 100y = 55x-5000            divide both sides by 100
  • y = 0.55x-50

The slope intercept form of this equation is:

y= 0.55x-50

4 0
3 years ago
Read 2 more answers
Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1
algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
2 years ago
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